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y^2-24y+135=0
a = 1; b = -24; c = +135;
Δ = b2-4ac
Δ = -242-4·1·135
Δ = 36
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{36}=6$$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-24)-6}{2*1}=\frac{18}{2} =9 $$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-24)+6}{2*1}=\frac{30}{2} =15 $
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